4t-2t+t^2=6t^2

Solution for 4t-2t+t^2=6t^2 equation:

4t-2t+t^2=6t^2

We move all terms to the left:

4t-2t+t^2-(6t^2)=0

determiningTheFunctionDomain
t^2-6t^2+4t-2t=0

We add all the numbers together, and all the variables

-5t^2+2t=0

a = -5; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-5)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-5}=\frac{-4}{-10}
=2/5
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-5}=\frac{0}{-10}
=0
$